Java code to arrange the letters of a word in alphabetical order

Java program to arrange the letters of a word in alphabetical order.

import java.io.*;
class AlphabeticalOrder
{
static String n;
static int l;
public static void main(String args[]) throws IOException
 {
 BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
 System.out.print("Enter a word : ");
 n = br.readLine();
 l = n.length();
 alphabetical();
 }
 public static void alphabetical()
 {
 char b[] = new char[l];
 for(int i=0;i<l;i++)
 b[i] = n.charAt(i);
 char t;
 for(int j=0;j<l-1;j++)
 {
  for(int k=0;k<l-1-j;k++)
  {
   if(b[k]>b[k+1])
   {
    t=b[k];
    b[k]=b[k+1];
    b[k+1]=t;
   }
  }
  }
 System.out.println("\nOriginal word : " +n);
 System.out.print("Sorted word : ");
 for(int m=0;m<l;m++)
  System.out.print(b[m]);
 System.out.print("\n");
 }
}

ALGORITHM:-

1. Start

2. Accept a word from the user.

3. Convert each letter of the word to its corresponding ASCII value.

4. Compare each letter of the word by its next letter and swap them if the first letter has a greater ASCII value than the next one.

5. Repeat the above procedure until the entire word is sorted.

6. Print the new word.

7. End

OUTPUT:-

Enter a word : computer

Original word : computer

Sorted word : cemoprtu

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