/* C program to check given grammar is Regular Grammar or not. */
#include<stdio.h>
#include<string.h>
int i,j,k,l,m,n=0,o,p,nv,z=0,t,x=0;
char str[10],temp[10],temp2[10],temp3[10];
struct prod
{
char lhs[10],rhs[10][10];
int n;
}pro[10];
void findter()
{
for(k=0;k<n;k++)
{
if(temp[i]==pro[k].lhs[0])
{
for(t=0;t<pro[k].n;t++)
{
for(x=0;x<10;x++)
temp2[x]='\0';
for(l=i+1;l<strlen(temp);l++)
temp2[l-i-1]=temp[l];
temp[i]='\0';
for(l=0;l<strlen(pro[k].rhs[t]);l++)
temp[i+l]=pro[k].rhs[t][l];
strcat(temp,temp2);
if(str[i]==temp[i])
return;
}
}
}
}
void main()
{
FILE *f;
for(i=0;i<10;i++)
pro[i].n=0;
f=fopen("tab3.txt","r");
while(!feof(f))
{
fscanf(f,"%s",pro[n].lhs);
if(n>0)
{
if( strcmp(pro[n].lhs,pro[n-1].lhs) == 0 )
{
pro[n].lhs[0]='\0';
fscanf(f,"%s",pro[n-1].rhs[pro[n-1].n]);
pro[n-1].n++;
continue;
}
}
fscanf(f,"%s",pro[n].rhs[pro[n].n]);
pro[n].n++;
n++;
}
n--;
printf("\n\nTHE GRAMMAR IS AS FOLLOWS\n\n");
for(i=0;i<n;i++)
for(j=0;j<pro[i].n;j++)
printf("%s -> %s\n",pro[i].lhs,pro[i].rhs[j]);
o=0;
for(i=0;i<n;i++)
{
for(j=0;j<pro[i].n;j++)
if( pro[i].rhs[j][0]>=65 && pro[i].rhs[j][0]<=90 )
{
o=1;
break;
}
if(o==1)
break;
}
if(i==n)
printf("\n\nTHE GRAMMAR is a REGULAR GRAMMAR !!!");
else
{
printf("\n\nTHE GRAMMAR is NOT a REGULAR GRAMMAR !!!");
exit(1);
}
while(1)
{
for(x=0;x<10;x++)
str[x]='\0';
printf("\n\nENTER ANY STRING ( 0 for EXIT ) : ");
scanf("%s",str);
if(str[0]=='0')
exit(1);
for(j=0;j<pro[0].n;j++)
{
for(x=0;x<10;x++)
temp[x]='\0';
strcpy(temp,pro[0].rhs[j]);
m=0;
for(i=0;i<strlen(str);i++)
{
if(str[i]==temp[i])
m++;
else if(str[i]!=temp[i] && temp[i]>=65 && temp[i]<=90)
{
findter();
if(str[i]==temp[i])
m++;
}
}
for(x=0;x<10;x++)
temp3[x]='\0';
strcpy(temp3,temp);
temp3[strlen(temp)-1]='\0';
//printf("%s",temp);
if(m==strlen(str) && strcmp(temp3,str)==0 && strlen(temp3)!=1)
{
printf("\n\nTHE STRING can be PARSED !!!");
break;
}
if(m==strlen(str) && strlen(str)==strlen(temp))
{
printf("\n\nTHE STRING can be PARSED !!!");
break;
}
}
if(j==pro[0].n)
printf("\n\nTHE STRING can NOT be PARSED !!!");
}
printf("\n\n");
}
Input File Regular Grammar Program:
S aS
S aB
B c
A pA
A p
For more C programs related to Automata, Check Automata label. Share and comment to improve this blog.
Related Programs:-
★ SLR Parser
★ Context Free Grammar (CFG)
★ DFA (Deterministic Finite Automata)
★ NFA (Non-Deterministic Finite Automata)
★ Convert NFA to DFA
#include<stdio.h>
#include<string.h>
int i,j,k,l,m,n=0,o,p,nv,z=0,t,x=0;
char str[10],temp[10],temp2[10],temp3[10];
struct prod
{
char lhs[10],rhs[10][10];
int n;
}pro[10];
void findter()
{
for(k=0;k<n;k++)
{
if(temp[i]==pro[k].lhs[0])
{
for(t=0;t<pro[k].n;t++)
{
for(x=0;x<10;x++)
temp2[x]='\0';
for(l=i+1;l<strlen(temp);l++)
temp2[l-i-1]=temp[l];
temp[i]='\0';
for(l=0;l<strlen(pro[k].rhs[t]);l++)
temp[i+l]=pro[k].rhs[t][l];
strcat(temp,temp2);
if(str[i]==temp[i])
return;
}
}
}
}
void main()
{
FILE *f;
for(i=0;i<10;i++)
pro[i].n=0;
f=fopen("tab3.txt","r");
while(!feof(f))
{
fscanf(f,"%s",pro[n].lhs);
if(n>0)
{
if( strcmp(pro[n].lhs,pro[n-1].lhs) == 0 )
{
pro[n].lhs[0]='\0';
fscanf(f,"%s",pro[n-1].rhs[pro[n-1].n]);
pro[n-1].n++;
continue;
}
}
fscanf(f,"%s",pro[n].rhs[pro[n].n]);
pro[n].n++;
n++;
}
n--;
printf("\n\nTHE GRAMMAR IS AS FOLLOWS\n\n");
for(i=0;i<n;i++)
for(j=0;j<pro[i].n;j++)
printf("%s -> %s\n",pro[i].lhs,pro[i].rhs[j]);
o=0;
for(i=0;i<n;i++)
{
for(j=0;j<pro[i].n;j++)
if( pro[i].rhs[j][0]>=65 && pro[i].rhs[j][0]<=90 )
{
o=1;
break;
}
if(o==1)
break;
}
if(i==n)
printf("\n\nTHE GRAMMAR is a REGULAR GRAMMAR !!!");
else
{
printf("\n\nTHE GRAMMAR is NOT a REGULAR GRAMMAR !!!");
exit(1);
}
while(1)
{
for(x=0;x<10;x++)
str[x]='\0';
printf("\n\nENTER ANY STRING ( 0 for EXIT ) : ");
scanf("%s",str);
if(str[0]=='0')
exit(1);
for(j=0;j<pro[0].n;j++)
{
for(x=0;x<10;x++)
temp[x]='\0';
strcpy(temp,pro[0].rhs[j]);
m=0;
for(i=0;i<strlen(str);i++)
{
if(str[i]==temp[i])
m++;
else if(str[i]!=temp[i] && temp[i]>=65 && temp[i]<=90)
{
findter();
if(str[i]==temp[i])
m++;
}
}
for(x=0;x<10;x++)
temp3[x]='\0';
strcpy(temp3,temp);
temp3[strlen(temp)-1]='\0';
//printf("%s",temp);
if(m==strlen(str) && strcmp(temp3,str)==0 && strlen(temp3)!=1)
{
printf("\n\nTHE STRING can be PARSED !!!");
break;
}
if(m==strlen(str) && strlen(str)==strlen(temp))
{
printf("\n\nTHE STRING can be PARSED !!!");
break;
}
}
if(j==pro[0].n)
printf("\n\nTHE STRING can NOT be PARSED !!!");
}
printf("\n\n");
}
Input File Regular Grammar Program:
S aS
S aB
B c
A pA
A p
For more C programs related to Automata, Check Automata label. Share and comment to improve this blog.
Related Programs:-
★ SLR Parser
★ Context Free Grammar (CFG)
★ DFA (Deterministic Finite Automata)
★ NFA (Non-Deterministic Finite Automata)
★ Convert NFA to DFA
i want ll1 in python or java
ReplyDeletelike this
S->aA|bB
A->a
B->b
this code can't run
ReplyDelete40 11 D:\prog\rony\Dev-Cpp\regular grammar.cpp [Error] '::main' must return 'int'
D:\prog\rony\Dev-Cpp\regular grammar.cpp In function 'int main()':
89 15 D:\prog\rony\Dev-Cpp\regular grammar.cpp [Error] 'exit' was not declared in this scope
99 19 D:\prog\rony\Dev-Cpp\regular grammar.cpp [Error] 'exit' was not declared in this scope
This is written & tested on Turbo C. If you are using other compiler than modify code according to you compiler.
DeleteThis comment has been removed by a blog administrator.
ReplyDeletef=fopen("tab3.txt","r");
ReplyDeletewhere is this file????
in your current working directory
DeleteEx :if your .c file is on Desktop then your .txt file should also be on Desktop